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2^x=3^y=12^z show that x=2yz/y-z-Answer by lenny460(1073) (Show Source) You can put this solution on YOUR website! Section 56 Conservative Vector Fields For problems 1 – 4 determine if the vector field is conservative →F = (2xy3 excos(y))→i (exsin(y) −3x2y2)→j F → = ( 2 x y 3 e x cos ( y)) i → ( e x sin ( y) − 3 x 2 y 2) j → →F = (xy2 −3y4 2)→i (xy2 x2y2−x)→j F → = ( x y 2 − 3 y 4 2) i → ( x y



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Check here stepbystep solution of 'If 2^x = 3y = 12^z then show that 1/z = 1/y 2/x' questions at Instasolv!Get an answer for 'xz=1 2xyz=3 x2yz=1' and find homework help for other Math questions at eNotes Search this site Go Latest answer posted at PMAssuming that , you may multiply the first equation by x, the second equation by y, the third equation by z, such that You need to factor out x,y and z, such that You need to notice that the
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= xyz = RHS Hence, proved 22 If a = c z, b = a x and c = b y, prove that xyz = 1 Solution It is given that a = c z, b = a x and c = b y We can write it as a = (b y) z where c = b y So we get a = b yz Here a = (a x) yz ⇒ a 1 = a xyz By comparing both2 3\pi e x^{\square} 0 \bold{=} Go Related » Graph » Number Line » Similar » Examples » Our online expert tutors can answer this problem Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!Apply the product rule to x 2 y x 2 y ( x 2) 2 y 2 z 4 x y 2 ( x y z) 2 ( x 2) 2 y 2 z 4 x y 2 ( x y z) 2 Multiply the exponents in ( x 2) 2 ( x 2) 2 Tap for more steps Apply the power rule and multiply exponents, ( a m) n = a m n ( a m) n = a m n



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If 2^x = 3^y = 12^z ,show that 1z = 1y 2x6 Apply the divergence theorem to an electrostatic field We have examined several versions of the Fundamental Theorem of Calculus in higher dimensions that relate the integral around an oriented boundary of a domain to a "derivative" of that entity on the oriented domain In this section, we state the divergence theorem, which is theX = y log_23 = z log_2 12 ⇒ x = ylog_23 = z(2log_22log_23) ⇒ x = y log_23 = z (2log_23) Now, z = x/2log_23 , y =x/log_23 ⇒log_23 = x2_z/z, log_23 = x/y ⇒x2z/z = x/y ⇒xy2yz = xz ⇒xy = xz 2y3 Divide by xyz




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Subtract 3 y from both sides 2x=123y 2 x = 1 2 − 3 y Divide both sides by 2 Divide both sides by 2 \frac {2x} {2}=\frac {123y} {2} 2 2 x = 2 1 2 − 3 y Dividing by 2 undoes the multiplication by 2 Dividing by 2 undoes the multiplication by 21 Inform you about time table of exam 2 Inform you about new question papers 3 New video tutorials informationPolynomial identities (short multiplication formulas) (x y) 2 = x 2 2xy y 2 (x y) 2 = x 2 2xy y 2 Example 1 If x = 10, y = 5a (10 5a) 2 = 10 2 2·10·5a (5a) 2 = 100 100a 25a 2 Example 2 if x = 10 and y is 4 (10 4) 2 = 10 2 2·10·4 4 2 = 100 80 16 = 36 The opposite is also true 25 a 4a 2 = 5 2




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Find all the zeroes of the polynomial 2xcube xsquare 6x 3 if 2 of its zeroes are √3 and √3 IF one of the zeros of quadratic polynomial is f(x)=14x²42k²x9 is negative of the other, find the value of k Answer When x = 9 and y = 16, the two expressions are (√9 √16) 2 and 9 16 The first expression simplifies to 49, and the second simplifies to 25 The two expressions are not equal Question 4 Show that (x y) 1 is not equal to when x = 9 and y = 16Question Find a potential function for the vector field \(F(x,y,z) = (z^{3}2xy^{2}, z^{2}2x^{2}y, 3xz^{2}2yz)\) (z^{3}2xy^{2}, z^{2}2x^{2}y, 3xz^{2}2yz)\) Best Answer This is the best answer based on feedback and ratings Previous question Next question Get more help from Chegg Solve it with our calculus problem solver and



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Subtract 2 from 5 to get 3 y=3x3_x=3(5)14_z=5 Multiply 3 by each term inside the parentheses y=3x3_x=1514_z=5 Add 14 to 15 to get 1 y=3x3_x=1_z=5 Replace all occurrences of x with the solution found by solving the last equation for x In this case, the value substituted is 1 y=3(1)3_x=1_z=5 Multiply 3 by each term inside the Solution Let us consider Take logarithm on both sides x log 2 = log k ;Then type x=3 Try it now 2x @ x=3 Clickable Demo Try entering 2x @ x=3 into the text box After you enter the expression, Algebra Calculator will evaluate 2x for x=3 2(3) = 6 More Examples Here are more examples of how to evaluate expressions in Algebra Calculator Feel free to try them now Evaluate 3xy for x=2, y=3 3xy @ x=2, y=3




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Get FREE NCERT Solutions for Class 9 Maths Chapter 2 Polynomials Ex 25 We have created Step by Step solutions for Class 9 maths to help you to revise$(abc)(a^2b^2c^2abbcca)=\dfrac12(xy)^2(yz)^2(zx)^2\cdot\dfrac12(ab)^2(bc)^2(ca)^2$ Now, I got into a mess I have got two products with sum of three squares which I cannot manage nor can I show this to be a perfect square Given that 3^x = 4^y = 12^z, show that z = (xy)/ (xy) Highestoffives is waiting for your help Add your answer and earn points




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Cydney Seigerman, Magoosh Tutor Hi Samuel ) We can actually solve for the individual variables in this question to subsequently find the product 12xyz x = 10 y = /3 z = 5 12xyz = 12*10*/3*5 = 4*10**5 = 4000 As you can see, solving for the individual variables and then finding the product takes several more steps than the approachSubtracting (A){(B) we get ‚(x ¡ 2y) = 0, so either ‚ = 0 or x = 2yBut ‚ = 0 would give x = y = z = 0, and f(0;0;0) = 0 is obviously not the maximumTherefore we work with x = 2y Subtracting (B){ we get ‚(2y¡3z) = 0, and since we already discarded the case ‚ = 0 we are left with z = 2 3 y Using the results in the two frames into (D) we get(xyz)^3 (x y z)(x y z)(x y z) We multiply using the FOIL Method x * x = x^2 yz yz = 2yz Therefore x^2 y^2 z^2 2xy 2xz 2yz (x^2 y^2 z^2 2xy 2xz yz)(x y z) x^2 * x = x^3 x^2 * y = x^2y x^2 * z = x^2z y^2 * x = y^2x y^2




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Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music Solution 2 x = 3 y = (12) z = k 2 x = k, 3 y = k, (12) z = k 2 = k 1/x, 3 = k 1/y, 12 = k 1/z 12 = 2 2 x 3 k1/z = (k 1/x) 2 x k 1/y k1/z = k 1/x x 2 x k 1/ Since, (a m) n = a mn k1/z = k 2/x x k 1/y k1/z = k 2/x1/y Since, am x an = amnClick HERE to return to the list of problems SOLUTION 14 Begin with x2/3 y2/3 = 8 Differentiate both sides of the equation, getting (Remember to use the chain rule on D ( y2/3 ) ) so that (Now solve for y ' ) Since lines tangent to the graph will have slope $ 1 $ , set y ' =




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It's clear zero is a solution and moreover x y z ≥ 0 Let's prove there are no more solutions over the integers By the generalized mean theorem x 2 y 2 z 2 3 > x y z 3 Which leads to x 2 y 2 z 2 > 3 ( x y z) 2 / 3 So now we know that whenever 3 ( x y z) 2 / 3 > 2 x y z there are no solutions ∴ x 2 y 2 z 2 = 24 We know that x 3 y 3 z 3 − 3xyz = (x y z)( x 2 y 2 z 2 − xy − yz − zx) = 8(24 −) = 8(4) = 32 Recommend (8) Comment (0) person Offered for classes 612, LearnNext is a popular selflearning solution for students who strive for excellence Explore Animated Video lessons All India Test SeriesZ log 12 = log k




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Start your free trial In partnership with You are being redirected to Course Hero ITo raise a power to another power, multiply the exponents Multiply 2 and 4 to get 8 2x^ {2}y^ {3}z^ {3}\times 81x^ {4}y^ {8}z^ {4} Calculate 3 to the power of 4 and get 81 162x^ {2}y^ {3}z^ {3}x^ {4}y^ {8}z^ {4} Multiply 2 and 81 to get 162 162x^ {6}y^ {3}z^ {3}y^ {8}z^ {4} EZ as pi Despite the fact that the same variables appear in every term, this expression does not factorize into one term There is no common factor, and no common bracket EAch term can be factored by differemce of squares xy(x2 − y2) yz(y2 − z2) zx(z2 − x2) = xy(x y)(x − y) − yz(y z)(y − z) zx(z x)(z − x



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Free system of equations calculator solve system of equations stepbystep To ask any doubt in Math download Doubtnut https//googl/s0kUoeQuestion If 2^x = 3^y =12^z show that 1/z= 1/y2/x About Press Copyright Contact us Creators AdvertiseAnswer (1 of 9) Let 2^x = 3^y = 6^{z} = k \implies 2 = k^{1/x} , 3 = k^{1/y} , 6 = k^{1/z} 6 = 2 × 3 \implies k^{1/z} = k^{1/x} × k^{1/y} \implies k^{ \frac{1



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= 0(x 2 y 2 z 2 – xy yzzx) (∵ x y z = 0 given) = 0 => x 3 y 3 z 3 = 3xyz Hence proved Ex 25 Class 9 Maths Question 14 Without actually calculating the cubes, find the value of each of the following (i) (12) 3 (7) 3 (5) 3 (ii) (28) 3 (15) 3 (13) 3 Solution (i) We know that, x 3 y 3 z 3 – 3xyz = (x y z(a) Sgiven by z= x2y2, 1 x 1, 1 y 1 oriented positive up Calculate RR S Fd~ S~ for F~= x~i y~j z~k (b) Sis the surface of 4x2 4y2 z2 6z 5 = 0 oriented inward Calculate the surface area of S (c) S is the surface of intersection of the sphere x2 y2 z2 4 and the plane z = 1 oriented away from the origin Calculate theFirst week only $499!




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